Tesla.Angela 发表于 2010-3-6 23:11:32

VB中字节数组和其他数据类型之间的转化

本帖最后由 Tesla.Angela 于 2010-3-6 23:15 编辑


Private Declare Sub CopyMemory Lib "kernel32" Alias "RtlMoveMemory" (Destination As Any, Source As Any, ByVal Length As Long)
Private Sub Command1_Click()
    Dim test(0 To 3) As Byte
    Dim i As Long, j As Long
    i = 1000
    '从long转化为byte数组
   CopyMemory test(0), i, 4
   '从byte数组转化为long
   CopyMemory j, test(0), 4
   MsgBox j
End Sub
'或者根据下面的代码中的函数进行转换:
Public Function HiByte(ByVal wParam As Integer) As Byte
'note: VB4-32 users should declare this function As Integer
   HiByte = (wParam And &HFF00&) \ (&H100)
End Function
Public Function LoByte(ByVal wParam As Integer) As Byte
'note: VB4-32 users should declare this function As Integer
   LoByte = wParam And &HFF&
End Function
Public Function HiWord(wParam As Long) As Integer
   If wParam And &H80000000 Then
      HiWord = (wParam \ 65535) - 1
   Else
      HiWord = wParam \ 65535
   End If
End Function
Public Function LoWord(wParam As Long) As Integer
   If wParam And &H8000& Then
      LoWord = &H8000& Or (wParam And &H7FFF&)
   Else
      LoWord = wParam And &HFFFF&
   End If
End Function
Public Function LoWordCM(wParam As Long) As Integer
'using API
   CopyMemory LoWordCM, wParam, 2
End Function
Public Function LShiftWord(ByVal w As Integer, ByVal c As Integer) As Integer
   Dim dw As Long
   dw = w * (2 ^ c)
   If dw And &H8000& Then
      LShiftWord = CInt(dw And &H7FFF&) Or &H8000&
   Else
      LShiftWord = dw And &HFFFF&
   End If
End Function
Public Function RShiftWord(ByVal w As Integer, ByVal c As Integer) As Integer
   Dim dw As Long
   If c = 0 Then
      RShiftWord = w
   Else
      dw = w And &HFFFF&
      dw = dw \ (2 ^ c)
      RShiftWord = dw And &HFFFF&
   End If
End Function
'两个byte转换为一个integer
Public Function MakeWord(ByVal bHi As Byte, ByVal bLo As Byte) As Integer
   If bHi And &H80 Then
      MakeWord = (((bHi And &H7F) * 256) + bLo) Or &H8000&
   Else
      MakeWord = (bHi * 256) + bLo
   End If
End Function
'两个integer转换为一个long
Public Function MakeDWord(wHi As Integer, wLo As Integer) As Long
   If wHi And &H8000& Then
      MakeDWord = (((wHi And &H7FFF&) * 65536) Or _
                  (wLo And &HFFFF&)) Or &H80000000
   Else
      MakeDWord = (wHi * 65535) + wLo
   End If
End Function


http://blog.csdn.net/gxj022/archive/2007/11/21/1896288.aspx

oopww 发表于 2010-3-9 21:05:00

这个有什么用啊!?

本网站最菜的人 发表于 2010-3-12 20:39:54

HoviDelphic 发表于 2010-3-12 22:23:16

貌似可以用HOOK转化
本网站最菜的人 发表于 2010-3-12 20:39 http://www.m5home.com/bbs/images/common/back.gif


    你说说看。
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